Partition the array into three equal sum segments

Repeated Character Whose First Appearance is Leftmost

Given a string, find the repeated character present first in the string.

Examples:


Input  : geeksforgeeks
Output : g
(mind that it will be g, not e.)

Input  : abcdabcd
Output : a

Input  : abcd
Output : -1
No character repeats

Asked in: Goldman Sachs internship

We have discussed different approaches in Find repeated character present first in a string.

How to solve this problem using one traversal of input string?

Method 1 (Traversing from Left to Right) We traverse the string from left to right. We keep track of the leftmost index of every character. If a character repeats, we compare its leftmsot index with current result and update the result if result is greater

#include <bits/stdc++.h>

using namespace std;

#define NO_OF_CHARS 256

int firstRepeating(string& str)

{

int firstIndex[NO_OF_CHARS];

for (int i = 0; i < NO_OF_CHARS; i++)

firstIndex[i] = -1;

int res = INT_MAX;

for (int i = 0; i < str.length(); i++) {

if (firstIndex[str[i]] == -1)

firstIndex[str[i]] = i;

else

res = min(res, firstIndex[str[i]]);

}

return (res == INT_MAX) ? -1 : res;

}

int main()

{

string str = "geeksforgeeks";

int index = firstRepeating(str);

if (index == -1)

printf("Either all characters are "

"distinct or string is empty");

else

printf("First Repeating character"

" is %c",

str[index]);

return 0;

}

Output:


First Repeating character is g

Time Complexity : O(n). It does only one traversal of input string.
Auxiliary Space : O(1)

Method 2 (Traversing Right to Left) We traverse the string from right to left. We keep track of the visited characters. If a character repeats, we update the result.

#include <bits/stdc++.h>

using namespace std;

#define NO_OF_CHARS 256

int firstRepeating(string& str)

{

bool visited[NO_OF_CHARS];

for (int i = 0; i < NO_OF_CHARS; i++)

visited[i] = false;

int res = -1;

for (int i = str.length() - 1; i >= 0; i--) {

if (visited[str[i]] == false)

visited[str[i]] = true;

else

res = i;

}

return res;

}

int main()

{

string str = "geeksforgeeks";

int index = firstRepeating(str);

if (index == -1)

printf("Either all characters are "

"distinct or string is empty");

else

printf("First Repeating character"

" is %c",

str[index]);

return 0;

}

Output:


First Repeating character is g

Time Complexity : O(n). It does only one traversal of input string.
Auxiliary Space : O(1)

The method 2 is better than method 1 as it does fewer comparisons.

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