In this post we will write a program to implement Stack using Linked List. Let’s first understand what is a Stack:
Stack:
A stack is an abstract data type that serves as a collection of elements, with two principal operations: push, which adds an element to the collection, and pop, which removes the most recently added element that was not yet removed. The order in which elements come off a stack gives rise to its alternative name, LIFO (for last in, first out).
Below image will make it clear:
There are two ways to implement Stack in C C++
- Using Array
- Using Linked List
Here I’ve Discussed how to implement Stack using Linked List.
C++ Program to implement Stack using Linked List:
#include<iostream>
using namespace std;
// Creating a NODE Structure
struct node
{
int data;
struct node *next;
};
// Creating a class STACK
class stack
{
struct node *top;
public:
stack() // constructor
{
top=NULL;
}
void push(); // to insert an element
void pop(); // to delete an element
void show(); // to show the stack
};
// PUSH Operation
void stack::push()
{
int value;
struct node *ptr;
cout<<"\nPUSH Operationn";
cout<<"Enter a number to insert: ";
cin>>value;
ptr=new node;
ptr->data=value;
ptr->next=NULL;
if(top!=NULL)
ptr->next=top;
top=ptr;
cout<<"\nNew item is inserted to the stack!!!";
}
// POP Operation
void stack::pop()
{
struct node *temp;
if(top==NULL)
{
cout<<"\nThe stack is empty!!!";
}
temp=top;
top=top->next;
cout<<"\nPOP Operation........\nPoped value is "<<temp->data;
delete temp;
}
// Show stack
void stack::show()
{
struct node *ptr1=top;
cout<<"\nThe stack is\n";
while(ptr1!=NULL)
{
cout<<ptr1->data<<" ->";
ptr1=ptr1->next;
}
cout<<"NULL\n";
}
// Main function
int main()
{
stack s;
int choice;
while(1)
{
cout<<"\n-----------------------------------------------------------";
cout<<"\n\t\tSTACK USING LINKED LIST\n\n";
cout<<"1:PUSH\n2:POP\n3:DISPLAY STACK\n4:EXIT";
cout<<"\nEnter your choice(1-4): ";
cin>>choice;
switch(choice)
{
case 1:
s.push();
break;
case 2:
s.pop();
break;
case 3:
s.show();
break;
case 4:
return 0;
break;
default:
cout<<"\nPlease enter correct choice(1-4)!!";
break;
}
}
return 0;
}OUTPUT:
-----------------------------------------------------------
STACK USING LINKED LIST
1:PUSH
2:POP
3:DISPLAY STACK
4:EXIT
Enter your choice(1-4): 1
PUSH Operation
Enter a number to insert: 12
New item is inserted to the stack!!!
-----------------------------------------------------------
STACK USING LINKED LIST
1:PUSH
2:POP
3:DISPLAY STACK
4:EXIT
Enter your choice(1-4): 1
PUSH Operation
Enter a number to insert: 5
New item is inserted to the stack!!!
-----------------------------------------------------------
STACK USING LINKED LIST
1:PUSH
2:POP
3:DISPLAY STACK
4:EXIT
Enter your choice(1-4): 2
POP Operation........
Poped value is 5
-----------------------------------------------------------
STACK USING LINKED LIST
1:PUSH
2:POP
3:DISPLAY STACK
4:EXIT
Enter your choice(1-4): 3
The stack is
12 ->NULL
-----------------------------------------------------------
STACK USING LINKED LIST
1:PUSH
2:POP
3:DISPLAY STACK
4:EXIT
Enter your choice(1-4): 4

Same as a my teacher dinesh chouhan sir
how to print this pattern
* *
** **
*** ***
********
#include
void main()
{
int i,j;
for(i=1; i <= 4 ;i++)
{
for(j=1;j <= (i*2);j++)
{
printf("*");
if((i == j)&& (i != 4) )
printf(" ");
}
printf("\n");
}
}
Spelling of constructor is construcTOR and not construcTURE
Thank you for mentioning.
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how to do a program in stack to convert infix to postfix;
Check this post:
https://proprogramming.org/program-to-convert-infix-to-postfix-in-c/
How would a PEEK function be implemented here?
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